說明
之前說過軸的選擇是快速排序法的效率關鍵之一,在這邊的快速排序法的軸選擇方式更加快了快速排序法的效率,它是來自演算法名書 Introduction to Algorithms 之中。
解法
先說明這個快速排序法的概念,它以最右邊的值s作比較的標準,將整個數列分為三個部份,一個是小於s的部份,一個是大於s的部份,一個是未處理的部份,如下所示 :
在排序的過程中,i 與 j 都會不斷的往右進行比較與交換,最後數列會變為以下的狀態:
然後將s的值置於中間,接下來就以相同的步驟會左右兩邊的數列進行排序的動作,如下所示:
整個演算的過程,直接摘錄書中的虛擬碼來作說明:
QUICKSORT(A, p, r) if p < r then q <- PARTITION(A, p, r) QUICKSORT(A, p, q-1) QUICKSORT(A, q+1, r) end QUICKSORT
PARTITION(A, p, r) x <- A[r] i <- p-1 for j <- p to r-1 do if A[j] <= x then i <- i+1 exchange A[i]<->A[j] exchange A[i+1]<->A[r] return i+1 end PARTITION
一個實際例子的演算如下所示:
實作
#include <stdio.h> #include <stdlib.h> #include <time.h> #define MAX 10 #define SWAP(x,y) {int t; t = x; x = y; y = t;}
int partition(int[], int, int); void quicksort(int[], int, int);
int main(void) { int number[MAX] = {0}; int i, num;
srand(time(NULL));
printf("排序前:"); for(i = 0; i < MAX; i++) { number[i] = rand() % 100; printf("%d ", number[i]); }
quicksort(number, 0, MAX-1);
printf("\n排序後:"); for(i = 0; i < MAX; i++) printf("%d ", number[i]); printf("\n");
return 0; }
int partition(int number[], int left, int right) { int i, j, s;
s = number[right]; i = left - 1;
for(j = left; j < right; j++) { if(number[j] <= s) { i++; SWAP(number[i], number[j]); } }
SWAP(number[i+1], number[right]); return i+1; }
void quicksort(int number[], int left, int right) { int q;
if(left < right) { q = partition(number, left, right); quicksort(number, left, q-1); quicksort(number, q+1, right); } }
public class QuickSort { public static void sort(int[] number) { sort(number, 0, number.length-1); } private static void sort(int[] number, int left, int right) { if(left < right) { int q = partition(number, left, right); sort(number, left, q-1); sort(number, q+1, right); }
}
private static int partition(int number[], int left, int right) {
int s = number[right]; int i = left - 1;
for(int j = left; j < right; j++) { if(number[j] <= s) { i++; swap(number, i, j); } }
swap(number, i+1, right); return i+1; }
private static void swap(int[] number, int i, int j) { int t; t = number[i]; number[i] = number[j]; number[j] = t; } }
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